Game Show Problem

bill · Intellectual Joined: 22 Apr 2006 Posts: 1204

Kemo you said it yourself "If it is indeed a proof mathematicians would recognize it" Therefore Jeffjo is no mathematician Shocked

QED Just another asshole wanna be.
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JeffJo · Intellectual Joined: 10 Mar 2009 Posts: 1019

bill · Intellectual Joined: 22 Apr 2006 Posts: 1204

Then how come the PhD I sent it to said otherwise. I received a letter from the mathematical association of America for my contributions to math. Especially My law of algebraic consistency. Since you were interested in math I thought I would help you out by showing you something new. But all you can do Jeffjo is jump to conclusions because you do not understand what I am trying to show you. So Jeffjo since I have been called to active duty I will not have time to play with you and Rob.
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JeffJo · Intellectual Joined: 10 Mar 2009 Posts: 1019

Kemosabe-TBC · Posted: Tue Dec 22, 2009 8:28 am Post subject:

Truth be told, I've never seen a mathematical proof with a dozen lines. You can't even prove that sqrt(2) is an irrational number with just that number of lines...

bill · Intellectual Joined: 22 Apr 2006 Posts: 1204

Yes Jeffjo it was a little bit more complete. But not much. You see Jeffjo truly gifted mathematicians see what others have overlooked. Sometimes because of all the competition, people like yourself work so hard at studying what others have discovered they fail to look for THEMSELVES.

If you go on the I Google site you will see optical illusions where some people see one picture and others see another. I always see both. Some people are blind to seeing any picture at all. They just see a bunch of lines and cannot make the connections.

Think about the story of Helen Keller. Think about Lenard Euler who when he finally went blind in both eyes stated "Oh now I see everything!" Euler knew he was going blind so he used to practice in the dark writing so when he finally went blind he could continue writing.

By the way Helen Keller had beautiful handwriting herself. Look at Ray Charles and Stevie Wonder. Sometimes it takes a man without sight to show a man with sight what he cannot see. To understand this watch the movie "Circle of Iron". There was also another true story about a women who was continually being raped and beaten by a demon. She went to a university for help and they devised a trap for the demon. They caught him or more correctly the demon let them catch him just to prove he was real. Then the demon broke free which the professors scientists engineers who set the trap thought was impossible.

You see Jeffjo I am trying to help you out of your hypnotic trance you have placed yourself in by studying so hard. You have become unable (not totally) to think for yourself on your own terms.

Imagine yourself in a world where math did not exist yet and you had to discover it and teach it to others. Then imagine yourself in my world where people believe the rules of math were etched in stone and it was heresy to try to write something new. And if you did if you even tried you were beaten and tortured until you recanted and renounced your discovery was wrong and evil and after you did this you were then put to death to save your soul.

Jeffjo I referred to in another post a book entitled An Imaginary Tale by Paul Nahin. It explains why you are wrong about your concept of the sets of numbers (you are also not wrong see the optical illusions I mentioned above). It explains why imaginary was a misnomer. And it explains why i is just as real as any other number. It explains how to find:

Integral from 0 to infinity of sin( x^2) not (sin(x))^2 which was a trivial integral.

Now you know how to take a standard integer derivative. But do you know how to take a fractional derivative. Instead of dny/dnx wher n is an integer dry/drx where r is a rational number.

You see Jeffjo math is all about the imagination and has nothing to do with the real world. The world we can understand. Naturally I am talking about pure math. Then there is applied math which explains natural phenomena and some anomalies. Then there are mathematical anomalies like larger and smaller infinities and larger and smaller zeros, where I had to rewrite what was etched in stone since before this universe began.

Do you play chess Jeffjo. If you did then you would be able to see what you are seeing wrong. I have lost games to rank amateurs but beaten experts at the game. It all depends my mood and frame of mind. I play chess with demons like the one I mentioned above who was beating and raping the woman in the movie I mentioned above. It is played on a board of 12 dimensions. Do you really think I have time to "explain everything" to you. Writing on this post to you Kemo and Rob is my "ludic" activities. The movies by the way do not even come close to the demons I battle. Get the picture Jeffjo. Now people like Rob remind me of the Spanish Inquisition going around shouting BILL IS A HERETIC BELIEVE ME BILL IS A HERETIC DO NOT BELIEVE A WORD HE SAYS

So I laugh at him and make fun of him. You on the other hand Jeffjo are a product of our poor educational system. You are very bright and very erudite. What you have learned; you have learned well; - too well. You have been indoctrinated and inoculated with knowledge but forgot that you have an imagination.

"LIFE JEFFJO IS TO BE IMAGINED NOT LIVED" "IF YOU CANNOT IMAGINE YOUR OWN LIFE IT WILL NEVER BE CREATED" "IT IS THE JOB OF OUR EDUCATORS TO ASSIST OUR CHILDREN IN IMAGINING THAT THEY CAN ALSO CREATE A LIFE FOR THEMSELVES" "A LIFE THEY CAN ASPIRE OTHERS WILL ADMIRE TOO"

Jeffjo do not indoctrinate and inoculate others with the knowledge that you know all too well teach them something new. Very Happy

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JeffJo · Intellectual Joined: 10 Mar 2009 Posts: 1019

bill · Intellectual Joined: 22 Apr 2006 Posts: 1204

Jeffjo prove it to yourself if you cannot you will never understand it.

You know nothing about me. You know nothing about what delusional means. How could you I have proven to all psychiatrists that they are delusional.

There are no steps missing just a simple explanation as to why?

So explain why it is a proof to yourself.
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JeffJo · Intellectual Joined: 10 Mar 2009 Posts: 1019

bill · Intellectual Joined: 22 Apr 2006 Posts: 1204

The answer to YOUR QUESTION is STARING YOU RIGHT IN YOUR FACE

Think about what you see Jeffjo do a compare and contrast essay on why there is a difference

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JeffJo · Intellectual Joined: 10 Mar 2009 Posts: 1019

bill · Intellectual Joined: 22 Apr 2006 Posts: 1204

Okay Jeffjo

(a+b)^2 = a^2 + b^2 + 2ab = d^2 or ; d^2 - 2ab = c^2 by hypothesis
(a-b)^2 =a^2 + b^2 - 2ab = f^2 or ; f^2 + 2ab = c^2 by hypothesis

Now we add the two and obtain:

2(a^2 + b^2) = d^2 + f^2 = 2c^2 from this we see two things 1) that it is a necessary condition that the R(ab) terms cancel each other out. 2) There exists a^2 + b^2 that equals c^2 it does tell us that such integers exist; it does not tell us what those integers are; it also tells us that there exist an infinite number of them. It also says there must be integers d^2 + f^2 that must equal 2c^2 In other words not just any a^2 + b^2 = c^2 This can easily be seen by plugging in integers. It is a necessary but not a sufficient condition. Now as you will see below this necessary condition of cancellation cannot be met for n greater than 2.

Now since a,b can be any two numbers this exhausts all possibilities by utilizing a+b and a-b. It also tells us that if there exist integers a,b,c for n greater than 2 it is a necessary condition that we must obtain the same outcome. So for n=3 we obtain following the same procedure:

a^3 + 3ab^2 = ( d^3 + f^3 )/2 = c^3 now since the b^3 cancels out this shows that it is not possible. But lets try this:

a^3 + b^3 + 3ab^2 - b^3 now between the sum of any two cubes and a third cube there always exists a difference because of the 3ab^2-b^3; the only time the R(ab) term disappears is when either a or b or both a and b are equal to zero unless of course 3ab^2 - b^3 can equal zero but since a is greater than b the difference is always positive. So for any a^3 + b^3 we have the following difference:

a^3 + b^3 is always different from c^3 . If there existed any a^3 +b^3 = c^3 then there would have to exist an a,b such that 3ab^2 - b^3 is zero. Our hypothesis was false.

Now for n=4

(a+b)^4 = a^4 + b^4 + 4a^3b + 6a^2(b^2) + 4b^3 and
(a-b)^4 = a^4 + b^4 - 4a^3b + 6a^2(b^2) - 4b^3

Adding we obtain a^4 + b^4 + 6a^2b^2 again because c^4 must be different our hypothesis that there exist an a^4 + b^4 = c^4 is wrong because the necessary condition that 6a^2(b^2) = zero can never be met when a, b are greater than zero.

Now I said is there another way:

(a^2 + b^2)^2 and (a^2 - b^2)^2 but then a^2 + b^2 must equal some f^2 or and a^2 - b^2 must equal some g^4 but then this contradicts the above because we have already established that we must eliminate 6a^2(b^2) in order for there to exist an a^4 + b^4 = c^4 and the only difference is the letters.

Now the same holds for all odd and even numbers n greater than 2. Since the necessary condition of cancellation of R(ab) can only be met for n=2 and not for n>2.
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JeffJo · Intellectual Joined: 10 Mar 2009 Posts: 1019

bill · Intellectual Joined: 22 Apr 2006 Posts: 1204

Jeffjo you just changed the name which means nothing. Then it is a necessary consequence in order for there to exist abc. You are mincing words and splitting hares.

It is necessary for this consequence to occur/happen/exist in order for such and such to be true.

It is necessary for this condition to occur/happen/exist in order for such and such to be true.

Anyone can change words of equivalent meanings Jeffjo. And then argue from there that there is a difference.

It is a necessary consequence/condition that the "terms cancel out". You are trying to play word games.

It tells us our hypothesis is true. But you have to deny this in order to say you are right and I am wrong. You assume your assumptions are right. My equation proves that the hypothesis of the existence of such numbers exist.

Jeffjo you argue ass backwards.

f and d are two numbers that are created by two other numbers a and b. According to the way you argue you could easily say a and b cannot be added or subtracted.

When you do a proof Jeffjo you start at a hypothesis which I did. Then I constructed two different equations that when added proved the hypothesis correct. You can argue and mince words until you are blue in the face Jeffjo. But mincing words and using semantics does not prove me wrong. It only proves you want to be right and the only person who is right can be you. You Jeffjo are not a mathematician you are a cynic.

My equations say such integers must exist Jeffjo not if they exist. But you deny this Jeffjo. I explain to you what the equations mean and the best you can do is deny what I say. This means either one of two things either you are breaking my balls (I do not mind I broke your balls) or you actually do not understand what a mathematical proof is unless you read it out of a math book.

So I will assume you are just breaking my balls.
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JeffJo · Intellectual Joined: 10 Mar 2009 Posts: 1019

On "necessary condition"